Respuesta :
Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:
[tex]A = a + (A \cap B)[/tex]
In which a is the probability that a customer saw the advertisement on the internet but not on television and [tex]A \cap B[/tex] is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:
[tex]B = b + (A \cap B)[/tex]
12% saw it on both the internet and on television.
This means that [tex]A \cap B = 0.12[/tex]
20% saw it on television
This means that [tex]B = 0.2[/tex]
37% of customers saw the advertisement on the internet
This means that [tex]A = 0.37[/tex]
What is the probability that a randomly selected customer saw the advertisement on the internet or on television
[tex]A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45[/tex]
45% probability that a randomly selected customer saw the advertisement on the internet or on television
