Respuesta :
Answer:
[tex] {x}^{2} - x - 2 \\ {x}^{2} - 2x + 1 x- 2 \\ {x}^{2} + 1x - 2 x- 2 \\ x(x + 1) - 2(x + 1) \\ = (x + 1)(x - 2)[/tex]
Answer:
[tex] {x}^{2} - x - 2 \\ {x}^{2} - 2x + 1 x- 2 \\ {x}^{2} + 1x - 2 x- 2 \\ x(x + 1) - 2(x + 1) \\ = (x + 1)(x - 2)[/tex]