Answer:
[tex]A=4.86\sqrt{3}\ m^2[/tex]
Step-by-step explanation:
The complete question in the attached figure
we know that
The area of triangle is given by the formula
[tex]A=\frac{1}{2}(b)(h)[/tex]
we have
[tex]h=5.4\ m[/tex] ----> given problem
Find the value of b
In the right triangle of the figure (a sail)
[tex]tan(60^o)=\frac{h}{b}[/tex] ---> by TOA (opposite side divided by the adjacent side)
we have
[tex]tan(60^o)=\sqrt{3}[/tex]
[tex]h=5.4\ m[/tex]
substitute
[tex]\sqrt{3}=\frac{5.4}{b}[/tex]
solve for b
[tex]b=\frac{5.4}{\sqrt{3}}=1.8\sqrt{3}\ m[/tex]
Find the area
[tex]A=\frac{1}{2}(1.8\sqrt{3})(5.4)[/tex]
[tex]A=4.86\sqrt{3}\ m^2[/tex]
