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2.50 L of a gas was at an unknown pressure. However, at standard pressure, its volume was measured to be 8.00L. Whats was the unknown pressure?

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olatunbosunadeoke

Answer: 2432 mmHg

Explanation:

Given that,

Original volume of gas V1 = 2.50L

Original pressure of gas P1 = ? (P1 is the unknown pressure)

New volume of gas V2 = 8.0L

New pressure of gas P2 = 760 mmHg

(Note that standard pressure a gas is 760 mmHg)

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

P1 x 2.50L = 760 mmHg x 8.00L

P1 x 2.50L = 6080 mmHg L

P1 = 6080 mmHg L / 2.50L

P1 = 2432 mmHg

Thus, the unknown pressure P1 is 2432 mmHg

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