The water in a pool is evaporating at a rate of 5% per day. If the pool has 15,600 gallons in it today, how many gallons will it have in 11 days? Round your answer to the nearest whole number, if necessary.

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Answer:

It will have 8873 gallons in 11 days.

Step-by-step explanation:

The amount of water in the pool after t years can be modeled by the following function:

[tex]A(t) = A(0)(1-r)^{t}[/tex]

In which A(0) is the initial amount of water and r is the daily rate of evaporation.

15,600 gallons in it today

This means that [tex]A(0) = 15600[/tex]

The water in a pool is evaporating at a rate of 5% per day.

This means that [tex]r = 0.05[/tex]. So

[tex]A(t) = A(0)(1-r)^{t}[/tex]

[tex]A(t) = 15600(0.95)^{t}[/tex]

How many gallons will it have in 11 days?

This is A(11). So

[tex]A(t) = 15600(0.95)^{11} = 8873[/tex]

It will have 8873 gallons in 11 days.

The number of gallons in 11 days is 8,873.

Given that,

  • The water in a pool is evaporating at a rate of 5% per day.
  • The pool has 15,600 gallons in it today.

Based on the above information, the calculation is as follows:

[tex]= 15,600 \times (1 - 0.05)^{11}\\\\= 15,600 \times (0.95)^{11}[/tex]

= 8,873

Therefore we can conclude that the number of gallons in 11 days is 8,873.

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