Respuesta :
Answer:
It will have 8873 gallons in 11 days.
Step-by-step explanation:
The amount of water in the pool after t years can be modeled by the following function:
[tex]A(t) = A(0)(1-r)^{t}[/tex]
In which A(0) is the initial amount of water and r is the daily rate of evaporation.
15,600 gallons in it today
This means that [tex]A(0) = 15600[/tex]
The water in a pool is evaporating at a rate of 5% per day.
This means that [tex]r = 0.05[/tex]. So
[tex]A(t) = A(0)(1-r)^{t}[/tex]
[tex]A(t) = 15600(0.95)^{t}[/tex]
How many gallons will it have in 11 days?
This is A(11). So
[tex]A(t) = 15600(0.95)^{11} = 8873[/tex]
It will have 8873 gallons in 11 days.
The number of gallons in 11 days is 8,873.
Given that,
- The water in a pool is evaporating at a rate of 5% per day.
- The pool has 15,600 gallons in it today.
Based on the above information, the calculation is as follows:
[tex]= 15,600 \times (1 - 0.05)^{11}\\\\= 15,600 \times (0.95)^{11}[/tex]
= 8,873
Therefore we can conclude that the number of gallons in 11 days is 8,873.
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