3. At the beginning of a titration to standardize the NaOH solution, Student A adjusted very carefully the initial burette volume to 0.00 mL, but he did not notice an important air bubble in the tip of the burette. At the end of the titration, the air bubble is gone. Explain the effect of that mistake on the calculated molarity MB. (Will the experimental MB calculated by Student A be higher or lower than the true MB value

Respuesta :

The molarity of the solution will be higher.

Explanation:

Standarization is a process in which the molarity of the solution is made to be known. The concentration determined is exact by this process.

To standarize the solution of NaOH, first the acid used for titration is taken in a flask say 10 ml, indicator and water (in this case 50 ml). Then biuret is filled with NaOH of known molarity and initial volume is noted.

The air bubble not taken notice of in this case will lower the volume as molarity is inversely proportional to volume. When volume decreases molarity increases and vice-versa.

Formula used is

molarity = [tex]\frac{number of moles}{volume in liters}[/tex]

The bubble will be formed with minimum volume thus volume is also lowered.

The impact of the mistake while determining the molarity should be that it should be higher.

What is Standardization?

It is the process where the solution molarity should be made and the concentration that should be measured should be exactly correct.

Here the air bubble should not be considered since it lowered the volume because the molarity should have an inverse relationship with the volume. That means the when there is the reduction in the volume so the molarity should be increased.

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