Answer:
5 m/s2
Explanation:
The equation of impulse for the exhaust gas leaving the rocket can be modeled as the following:
[tex]mv = F\Delta t[/tex]
where m is the mass of the exhaust gas, v is the speed of the exhaust gas, F is the force generated by exhaust gas leaving the rocket, and Δt is the time it takes. This equation can be transformed to the following:
[tex]F = mv/\Delta t = \dot{m}v = 6.6*103 = 679.8 N[/tex]
Using Newton 2nd law we can find the acceleration generated by this
[tex]a_e = F/M = 679.8 / 103 = 6.6 m/s^2[/tex]
Taking the moon gravity into account, the net acceleration would be
a = 6.6 - 1.6 = 5 m/s2
