Answer:
[tex]\dot W_{out} = 3863.98\,kW[/tex]
Explanation:
The turbine at steady-state is modelled after the First Law of Thermodynamics:
[tex]-\dot Q_{out} -\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0[/tex]
The specific enthalpies at inlet and outlet are, respectively:
Inlet (Superheated Steam)
[tex]h_{in} = 3353.1\,\frac{kJ}{kg}[/tex]
Outlet (Liquid-Vapor Mixture)
[tex]h_{out} = 890.1\,\frac{kJ}{kg}[/tex]
The power produced by the turbine is:
[tex]\dot W_{out}=-\dot Q_{out} + \dot m \cdot (h_{in}-h_{out})[/tex]
[tex]\dot W_{out} = -2.93\,kW + (1.57\,\frac{kg}{s} )\cdot (3353.1\,\frac{kJ}{kg} - 890.1\,\frac{kJ}{kg} )[/tex]
[tex]\dot W_{out} = 3863.98\,kW[/tex]
