Respuesta :
Answer:
With 800 extra kg load: speed = 66.667 km/h
With 2400 extra kg load: speed = 40 km/h
Step-by-step explanation:
Let's call the weight of the car W = 1600 kg, and its speed after accelerating for 8 seconds with this weight S = 100 km/h
If we load the car with 800 extra kg, the total weight will be:
W2 = W + 800 = 2400 kg
The relation between the weights is:
W2 / W = 2400 / 1600 = 1.5
If the weight increased 1.5 times, the relation between the speeds will be 1/1.5 (as they are inversely proportional), so:
S2 / S = 1 / 1.5
S2 = S / 1.5 = 66.667 km/h
If we load the car with 2400 extra kg, the total weight will be:
W3 = W + 2400 = 4000 kg
The relation between the weights is:
W3 / W = 4000 / 1600 = 2.5
If the weight increased 2.5 times, the relation between the speeds will be 1/2.5, so:
S3 / S = 1 / 2.5
S3 = S / 2.5 = 40 km/h
Answer:
66.67km/hr
Step -by - step explanation:
From what I understand from the question,The speed of a car after accelerating for 8 seconds is inversely proportional to its weight. The car weighs 1600 kg and accelerates to 100 km/h in 8 seconds. We were now asked to find the speed after accelerating for 8 seconds if we load the car with 800 extra kg to 2400 kg.
Speed of the car is inversely proportional to the weight of the car
S = k/w
For the first 8 seconds the car accelerate, the car weighed 1600kg and the speed was 100km/hr
100 = k/1600
K = 1600 × 100
K = 160,000
If an extra weight of 800kg was added,and the new weight of the car is 2400kg,the new speed of the car will be
S = 160000/2400
S = 66.67km/hr
