contestada

A 10.5 cm long solenoid contains 891 turns and carries a current of 5.95 A . What is the strength of the magnetic field at the center of this solenoid?

Respuesta :

AMB000

Answer:

B=0.06345T

Explanation:

The magnetic field at the center of the solenoid can be calculated with the formula:

[tex]B=\frac{\mu_0NI}{L}[/tex]

where [tex]\mu_0=4\pi\times10^{-7}N/A^2[/tex] is the vacuum permeability, and for our values is:

[tex]B=\frac{(4\pi\times10^{-7}N/A^2)(891)(5.95A)}{(0.105m)}=0.06345T[/tex]