Answer:
The launch angle = 67.38°
Explanation:
For projectile motion, the range (R) and maximum height (H) reached are represented by the formulas
R = (u² sin 2θ)/g
H = (u² sin² θ)/2g
H = (3/5) R
(H/R) = (3/5)
Dividing the formula for maximum height by that of the range of a projectile
(H/R) = [(sin² θ)/2] ÷ sin 2θ
Sin 2θ = 2 sinθcosθ
(H/R) = (sin² θ)/(2×2sinθcosθ)
(H/R) = (sin² θ)/(4sinθcosθ)
(H/R) = (sinθ)/(4cosθ) = (3/5)
Tanθ = (12/5)
θ = tan⁻¹ (2.4)
θ = 67.38°
