Two circular loops of wire, each containing a single turn, have the same radius of 5.1 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 1.5 A. What is the magnitude of the net magnetic field at the common center

Respuesta :

Answer:

[tex]2.6135\times10^-^5 T[/tex]

Explanation:

Using the equation and Pythagorean theorem, we find that magnitude of the net magnetic field at the center of the two loops is expressed as:

[tex]B_n=\sqrt{(\frac{N\mu_0I}{2R})^2+(\frac{N\mu_0I}{2R})^2}\\=\sqrt{2}(\frac{\N\mu_0I}{2R})\\=\frac{\sqrt{2}(1)(4\pi \times 10^-^7/T.m/A)(1.5A)}{2.0(0.040m)}\\=2.6135\times10^-^5 T[/tex]

Hence, the net magnitude at the common center is [tex]2.6135\times10^-^5 T[/tex]