The standard form or the equation of a parabola is y = 7x^2 + 14 +4. What is the vertex form of the equation? Can someone please explain how to get the answer. I am having a difficult time understanding the concept. Answers choices: y = 7(x + 2)^2 - 3 y = 7(x + 2)^2 + 3 y = 7(x + 1)^2 - 3 y = 7(x + 1)^2 + 3

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Answer:

Step-by-step explanation:

Given is the standard form of the equation of a parabola as

[tex]y = 7x^2 + 14 x+4[/tex]

We are to convert this into vertex form

Vertex form would be

[tex]y-k = a(x-h)^2[/tex], where (h,k) would be the vertx

To bring to this form we can use completion of squares method

[tex]y = 7x^2 + 14 x+4\\y=7(x^2+2x)+4\\y = 7[(x+1)^2-1]+4\\y=7[(x+1)^2-7+4\\y=7(x+1)^2-3[/tex]

So this would be the vertex form

Since we have x square and x term we suitably added a value so that the three terms made a perfect square.

Here added and subtracted 1.

Answer: y = 7x 2- 42x +67

Step-by-step explanation:

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