Answer:
308 N
Explanation:
Givens:
Weight of the salmon, w = 86 N
Initial speed of the fish v = 2.8 m/s.
The line should stop the fish in a distance d = 15 cm
Final speed of the fish v = 0 m/s.
From the kinematic equations of motion:
The deceleration of the fish is given by:
[tex]v^{2} =v_i^{2} + a2d\\0=2.8^2+2*15*10^-2[/tex]
a = -35.63 m/s
From Newton's second law of motion:
The vector sum of the forces F_net on the fish is equal to the its mass multiplied by its acceleration a. And the net force acting on the fish in this case is the tension force from the line and the weight of the fish but they are in opposite directions.
However, if the line is horizontal the tension force will represent the minimum strength needed for the line to stop the fish and it's given by:
| T | = m |a | = w/g * | a |*| T |
= 86/9.8 * 35.63
= 309 N
Where | T | is the minimum strength needed for the line to stop the fish.
m is the mass of the fish.
l a l is the magnitude of the acceleration of the fish.
note:
calculation maybe wrong but method is correct
