2) A 250.0 mL sample of nitrogen is collected at 25°C and an atmospheric pressure of 766.4 torr. What volume of
nitrogen would this be at STP?

Respuesta :

Answer: 231mL

Explanation:

P1 = 766.4 torr

V1 = 250mL

T1 = 25°C = 25 + 273 = 298K

P2 = stp = 760torr

T2 = stp = 273K

V2 =?

P1V1/T1 = P2V2/T2

(766.4x250)/298 = (760xV2) /273

298x760xV2 = 766.4x250x273

V2 = (766.4x250x273) /(298x760)

V2 = 231mL