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A particle of mass m scatters off a second particle with mass M according to a potential U(r) = α r 2 , α > 0 Initially m has a velocity v0 and approaches M with an impact parameter b. Assume m M, so that M can be considered to remain at rest during the collision. 1. Find the distance of closest approach of m to M. 2. Find the laboratory scattering angle. (Remember that M remains at rest.)

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Answer:

1). [tex]R = \frac{(b^2-\frac{2∝}{mv^2_0} )}{sin^2(V_0^2b^2-\frac{2∝}{m})^{1/2}t }[/tex]

where a = ∝

2). [tex]tan( \alpha__l}) = \frac{sin \alpha cm }{cos\alphacm+\frac{V__cm}{V__0} }[/tex]

where ∝ = θ for the above equation

Explanation:

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