The lowest frequency in the audible range is 20 Hz. What are the lengths of (a) the shortest open-open tube and (b) the shortest open-closed tube needed to produce this frequency?

Respuesta :

Answer:

length of the shortest open-open tube 8.6 m

length of the shortest open-closed tube 4.3 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open tube is given by

[tex]f_{1} =\frac{v}{2L}[/tex]

where v is the velocity of the air ,v=343 m/s  and L is the length

The length of open-open tube needed is

[tex]f_{1} =\frac{v}{2L} \\L=\frac{v}{2f_{1}} \\L=\frac{343}{2\times 20} \\L=8.6 m[/tex]

Fundamental frequency for standing wave mode of  an open- close tube is is given by

[tex]f_{1} =\frac{v}{4L}[/tex]

The length of open-close tube needed is

[tex]L=\frac{v}{4f_{1}} \\L=\frac{343}{4\times 20} \\L=4.3m[/tex]