Answer
given,
Power generated,P_0 = 4.3 MW
Power extracted = 24 MW
Temperature of source,T₁ = 108°C
Temperature of discharge,T₂ = 17°C
a) Actual efficiency
[tex]\eta =\dfrac{P_0}{Power\ extracted}\times 100[/tex]
[tex]\eta = \dfrac{4.3}{24}\times 100 [/tex]
[tex]\eta = 17.92\ \%[/tex]
b) Maximum theoretical efficiency
[tex]\eta_{max}=(1-\dfrac{T_2}{T_1})\times 100[/tex]
[tex]\eta_{max}=(1-\dfrac{273+17}{273+108})\times 100[/tex]
[tex]\eta_{max} = 23.88\ \%[/tex]
