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In the deep ocean, a water wave with wavelength 95 m travels at 12 m/s. Suppose a small boat is at the crest of this wave, 1.2 m above the equilibrium position. What will be the vertical position of the boat 5.0 s later?

Respuesta :

Answer:

the vertical position is 1.1971m

Explanation:

Recall that

[tex]y = 1.2 * cos (\frac{2*\pi * distance travelled}{wavelenght})[/tex]

recall that [tex]v = \frac{distance}{time}[/tex]

[tex]thus; distance = v* t[/tex]

this implies that distance = 12 * 5.0

                                          =  60

therefore;  [tex]y = 1.2 cos \frac{2*3.142*60}{95}[/tex]

                  y = 1.1971m

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