Answer:
[tex]Area\:shaded=\frac{3}{5} (2x+15)[/tex]
Step-by-step explanation:
Let [tex]s[/tex] be the shaded area and [tex]u[/tex] be the unshaded area, then we know that
(1). [tex]\frac{s}{u}=\frac{3}{2}[/tex]
and
(2). [tex]s+u=(2x+15)[/tex]
We solve for [tex]u[/tex] in the first equation and get:
[tex]u=\frac{2}{3}s[/tex]
and put this into the second equation and get:
[tex]s+\frac{2}{3}s=(2x+15)[/tex]
[tex]s(1+\frac{2}{3} )=(2x+15)[/tex]
[tex]s(\frac{5}{3} )=(2x+15)[/tex]
[tex]\boxed{s=\frac{3}{5} (2x+15)}[/tex]