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Iridium β is a solid phase of iridium still unknown to science. The only difference between it and ordinary iridium is that Iridium β forms a crystal with a bcc unit cell and a lattice constant a=314. pm . Calculate the density of Iridium β . Round your answer to 3 significant digits.

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Answer:

Here we’ll use atomic mass and atomic volume.

Iridium density, p=m/v,

for a BCC crystal, 2atoms/a³ = Nₐ atoms/Vₓ,, Na=avogadro constant =6.02 x  10²³ atoms,

therefore, Atomic Volume, Vₓ = 6.02 x  10²³ (314x10⁻⁸)³/2 cm³ = 9.319x10⁶cm³

Density of Iridiumβ,  ρ = Atomic mass / Atomic Volume = 192.21g/9.319x10⁶cm³

  2.06 x 10⁻⁵g/cm³ to 3s.f

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