Answer:
[tex]\{(t,2t-5)\ where\ t\in(-\infty,\infty)\}[/tex] is the solution set.
Step-by-step explanation:
[tex]y=2x-5......(1)\\3y=6x-15........(2)\\[/tex]
Divide eqn(2) by 3.
[tex]y=2x-5[/tex]
Hence both are the same lines.
if [tex]x=t[/tex] where [tex]t[/tex] be any point on real line iR.
from eqn (1)
[tex]y=2t-5[/tex]
Hence solution set is [tex]=\{(t,2t-5):t \in R)\}[/tex]
