The range of the projectile is 188 m
Explanation:
The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
The path of a projectile is the combination of these two motions: see figure in attachment.
In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.
We have:
t = 5.0 s (time of fligth of the projectile)
and the horizontal velocity is constant, and it is given by
[tex]v_x = v_i cos \theta[/tex]
where
[tex]v_i = 40 m/s[/tex] is the initial velocity
[tex]\theta=20^{\circ}[/tex] is the angle of projection
Substituting,
[tex]v_x = (40)(cos 20^{\circ})=37.6 m/s[/tex]
And therefore, the range of the projectile is:
[tex]d=v_x t = (37.6)(5.0)=188 m[/tex]
Learn more about projectile motion:
brainly.com/question/8751410
#LearnwithBrainly
