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A string is tied at both ends, and a standing wave is established. The length of the string is 2 m, and it vibrates in the fundamental mode ( n = 1).1) If the speed of waves on the string is 60 m/s, calculate the wavelength of the waves. (Express your answer as an integer.)2) If the speed of waves on the string is 60 m/s, calculate the frequency of the waves. (Express your answer to two significant figures.)

Respuesta :

Answer:

Wavelength = 1.33 m

Frequency = 721.80 Hz

Explanation:

Given that

Length ,L= 2 m

V= 60 m/s

The wavelength λ given as

[tex]\lambda =\dfrac{2 L}{3}[/tex]

[tex]\lambda =\dfrac{2\times 2}{3}[/tex]

λ  = 1.333 m

We know that the velocity given as

V = f λ

60= f x 1.33

f = 721.80 Hz

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