Answer:
δ = 2.5 π
Explanation:
Given that
d= 1.25 λ
d= Path length
We know that phase difference(δ) given as
[tex]\delta =2\pi \dfrac{dsin\theta}{\lambda}[/tex]
[tex]dsin\theta = 1.25\lambda[/tex]
Now by putting the value
[tex]\delta =2\pi \dfrac{dsin\theta}{\lambda}[/tex]
[tex]\delta =2\pi \dfrac{1.25\lambda}{\lambda}[/tex]
δ = 2.5 π
Therefore the phase difference will be 2.5π
