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An automobile engineer is revising a design for a conical chamber that was originally specified to be 12 inches long with a circular base diameter of 5.7 inches. In the new design, the chamber is scaled by a factor of 1.5. What is the volume of the revised chamber? Round your answer to two decimal places.

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The scale factor is 1.5, which means that the revised chamber is larger. The new dimensions are just the old dimensions times 1.5.

The volume of the revise chamber is:

V = (1/3) (PI) [(D/2)^2] (H)

= (1/3) (PI) {[(5.7)(1.5)/2]^2} [(12)(1.5)]

= 344.4874 in3

 

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