ChocolateIce ChocolateIce

06-12-2019
Mathematics

contestada

PLS HELP RN
1. What is the value of 4k + 6 (j - 2) when k = 3 and j = 5?
2. 9(r - 5) = 4r - 5

Respuesta :

gcantiga44 gcantiga44

06-12-2019

Answer:

1.

4k + 6(j - 2)

Substitute the values.

4(3) + 6 [(5) - 2]

12 + 6 (3)

12 + 18

= 30

2.

9(r - 5) = 4r - 5

9r - 45 = 4r - 5

9r - 4r - 45 = -5

5r - 45 = -5

5r = -5 + 45

5r = 40

r = 40 ÷ 5

r = 8

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