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A sample of chlorine gas is held at a pressure of 1023.6 kPa. When the pressure is decreased to 8114 kPa the
temperature is 36°C, What was the original temperature? Gas Law used:

Respuesta :

Neetoo

Answer:

T₁  = 39 K

Explanation:

Given data:

Initial pressure = 1023.6 kpa

Final pressure = 8114 kpa

Final temperature = 36°C (36+ 273= 309K)

Initial temperature = ?

Solution:

P₁/T₁ = P₂/T₂

T₁  = P₁×T₂ /P₂

T₁  = 1023.6 kpa × 309 K /8114 kpa

T₁  = 316292.4 K. Kpa /8114 kpa

T₁  = 39 K

Thus original pressure was 39 k.

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