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Historyislife
Do you have the 4th problem typed correctly? The two given numbers have no factor (other than 1) in common (i.e., they are relatively prime) so the GCF is 1. 

48 = 2^4 * 3 

Therefore, GCF of 16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 is 16a^2 b^4, so 
16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 = (16a^2 b^4)(a^2 + 2ab - 3b^2) = (16a

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