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Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g)+2H2(g)⇌C2H6(g) Given the following data at standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K), what is the value of Kp for this reaction? Substance ΔG∘f (kJ/mol) C2H2(g) 209.2 H2(g) 0 C2H6(g) −32.89

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codedmog101

Answer:1.01

Explanation:∆G(system)= ∆G(product) - ∆G(reactant)

Therefore, we have: -32 - 209.2 = -242.09 kj/mol.

Also, ∆G(system)= -RT ln kp ----{*}

R= 8.314, T= 298, kp =? , ∆G(system)= -242.09 kj/mol.

We can now substitute into equation {*}.

I.e, -242.09kj/mol= -8.314×298 ln kp

-242.09= -24477.572 ln kp

In kp= - 242.09÷ -24477.572

ln kp= 0.00989

kp= 1.0099.

~ 1.01

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