Answer:277.40 m
Explanation:
Given
Altitude of plane =84 m
Speed of plane=67 m/s
Time taken to cover 84 m
[tex]S=ut+\frac{at^2}{2}[/tex]
[tex]84=0+\frac{9.8\times t^2}{2}[/tex]
t=4.14 s
Horizontal distance=vt
[tex]=67\times 4.14=277.40[/tex]
Therefore Pilot must drop 277.40 m before the target.