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A robot on a basketball court needs to throw the ball in the hoop. The ball have a velocity of 10 m/s and an an angle of 60 degrees. The high of hoop is 0.75 meters and the horizontal distance between the robot and hoop is 5 meters. A) draw a digram.
B)What is the high that the robot needs to throw the ball from.

Respuesta :

Answer:

Initial velocity = 10 m/s

θ = 60°

This is the case of projectile motion

So the horizontal component of velocity 10 m/s  =  10 cosθ

u = 10 cosθ

u = 10 cos 60°

u=5 m/s

x= 5 m

So in the horizontal direction

x = u .t

5 = 5 .t

t = 1 sec  The vertical component of velocity 10 m/s = 10 sinθ

Vo= 10 sinθ

Vo= 10 sin 60°

Vo = 8.66 m/s

[tex]V^2=V_o^2+2gh[/tex]

[tex]0=V_o^2-2gh[/tex]

[tex]0=8.66^2-2\times 10\times h[/tex]

h=3.75 m

So height of robot = 3.75 - 0.75 m

   height of robot =3 m

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