Respuesta :
L = 6W
Area A = LW = 600. So, 6W(W) = 600, W2 = 600/6 = 100, so W = 10. Then L = 600/10 = 60.
Perimeter P = 2L + 2W = 2(60) + 2(10) = 120 + 20 = 140.
Area A = LW = 600. So, 6W(W) = 600, W2 = 600/6 = 100, so W = 10. Then L = 600/10 = 60.
Perimeter P = 2L + 2W = 2(60) + 2(10) = 120 + 20 = 140.
The perimeter of the rectangle is 140.
Given that,
- The area of the rectangle is [tex]600m^2.[/tex]
- Here the width be x.
- So, the length be 6x.
Now based on the above information,
We know that
[tex]Area\ of\ the\ rectangle = length \times width\\\\600 = 6x \times x \\\\600 = 6x^2\\\\x^2 = 100[/tex]
x = 10
That means the width be 10m
And, the length be 60m
Now the perimeter of the rectangle should be
[tex]= 2 \times (Length+width)\\\\= 2\times (10 + 60)\\\\= 2 \times 70[/tex]
= 140m
Therefore we can conclude that the perimeter of the rectangle is 140.
Learn more: brainly.com/question/16167300