contestada

A stone is thrown horizontally at a velocity of 12.38 m/s from a tree house that is
located 61.8 m above the ground in a beautiful redwood tree. What is the
magnitude of the stone's vertical component of velocity just before it hits the
ground?

Respuesta :

Answer:

34.8 m/s

Explanation:

Since we're only interested in vertical velocity we can ignore anything horizontal.

We have the following information (in the vertical direction)

d = 61.8

a = 9.8

vi = 0

vf = ?

The equation combining all these variables is:

[tex]v_f^2 = v_i^2 + 2ad\\v_f^2=0+2(9.8)(61.8)\\v_f^2=1211.28\\v_f=\sqrt{1211.28}\\v_f=34.8[/tex]