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Determine the mass of chloride (MW = 35.45 g/mol ) in grams present in 100 mL of a 0.273 M solution of aqueous FeCl₃ (iron(III) chloride). Express the mass in grams to three significant figures.

Respuesta :

Answer:

The mass chloride is 2.903 grams

Explanation:

Step1: calculate the moles of FeCl3

moles = molarity  x  volume  in liters

volume in liters = 100 ml /1000 =  0.1 L

molarity = 0.273  M  =  0.273  mol / L

moles   =   0.273  mol /L  x 0.1 L = 0.0273   moles

step 2:  find the moles of Cl

since there is  3  atoms of  cl in FeCl3

= 3 x 0.0273 =0.0819 moles

Step 3:  calculate  mass  of cl

 mass= moles  x molar mass

=0.0819 moles x 35.45 g/mol = 2.903 g

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