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From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 67-kg man in a spacecraft traveling in a circular orbit 263 km above the earth's surface. Express W in both newtons and pounds.

Respuesta :

Answer:

602.665 N

Explanation:

mass of man, m = 67 kg

height, h = 263 km

radius of earth, R = 6400 km

The value of acceleration due to gravity at this height is given by

[tex]g' = g\left ( 1-\frac{2h}{R} \right )[/tex]

[tex]g' = 9.8\left ( 1-\frac{2\times 263}{6400} \right )[/tex]

g' = 8.995 m/s^2

The weight of the person at this height is given by

W = m g'

W = 67 x 8.995 = 602.665 N

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