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A motorboat accelerates uniformly from a ve- locity of 7.0 m/s to the west to a velocity of 2.4 m/s to the west. If its acceleration was 2.7 m/s2 to the east, how far did it travel during the acceleration? Answer in units of m.

Respuesta :

Answer:

Distance, d = 8 meters

Explanation:

Given that,

Initial velocity of the motorboat, u = 7 m/s (west)

Final velocity of the motorboat, v = 2.4 m/s (west)

Acceleration of the motorboat, [tex]a=-2.7\ m/s^2[/tex] (east)

We need to find the distance covered by it. It can be calculated as :

[tex]v^2-u^2=2as[/tex]

[tex](2.4)^2-(7)^2=2\times (-2.7)s[/tex]

s = 8 meters

So, the distance covered by the motor boat is 8 meters. Hence, this is the required solution.

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