Answer:
Magnetic flux through the loop is 0.25 Weber.
Explanation:
It is given that,
Magnetic field, B = 0.2 T
Radius of circular loop, r = 0.5 m
Magnetic field is directed perpendicular to the plane of a circular loop, [tex]\theta'=90[/tex]
Using the formula of magnetic flux as :
[tex]\phi=BA\ cos\theta[/tex]
[tex]\phi=BA\ cos(90-\theta)[/tex]
[tex]\phi=BA\ sin(90)[/tex]
[tex]\phi=0.2\times \pi (0.2)^2[/tex]
[tex]\phi=0.025\ Wb[/tex]
So, the magnitude of the magnetic flux through the loop is 0.25 Weber. Hence, this is the required solution.
