Give the coordination number for each metal ion in the following compounds:
(a) [Co(CO3)3]3− (note that CO32− is bidentate in this complex)(b) [Cu(NH3)4]2+
(c) [Co(NH3)4Br2]2(SO4)3
(d) [Pt(NH3)4][PtCl4]
(e) [Cr(en)3](NO3)3
(f) [Pd(NH3)2Br2] (square planar)
(g) K3[Cu(Cl)5]
(h) [Zn(NH3)2Cl2]

Respuesta :

Answer: a. 6(3x2=6)

B. 4(4x1=4)

C. 6(4(1)+2(1)=4+2=6

D. 4

E. 6(3(2)=6)

F. 4(2(1)+2(1)[2+2=4)

G. 5(5(1)=5)

H. 4(2(1)+2(1)=2+2=4)

Explanation:

Coordination number= no of ligands

= No of ligands X denticity

Denticity is nothing but type of ligands like mono,do and tetradentate ligands.