Answer:
Option A) [tex]\frac{4x+3y}{3x-4y}[/tex]
Step-by-step explanation:
The given expression is:
[tex]\frac{\frac{x}{3}+\frac{y}{4}}{\frac{x}{4}-\frac{y}{3}}[/tex]
Taking LCM in upper and lower fractions, we get:
[tex]\frac{\frac{x}{3}+\frac{y}{4}}{\frac{x}{4}-\frac{y}{3}}\\\\ =\frac{\frac{4x+3y}{12}}{\frac{3x-4y}{12}}\\\\\text{Cancelling out the common factor 12, we get:}\\\\ =\frac{4x+3y}{3x-4y}[/tex]
Therefore, the option A gives the correct answer.
