A line passes through the point (-4,-8) and has a slope of -5/2.
Write an equation in slope-intercept form for this line..
Plz

Respuesta :

Here you go, and please mark brainliest :)
Ver imagen renas19

[tex]\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies -\cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=-\cfrac{5}{2}[x-(-4)] \\\\\\ y+8=-\cfrac{5}{2}(x+4)\implies y+8=-\cfrac{5}{2}x-10\implies y=-\cfrac{5}{2}x-18[/tex]