Respuesta :

[tex]X[/tex] has PDF

[tex]f_X(x)=\begin{cases}\dfrac1{14}&\text{for }-5<x<9\\\\0&\text{otherwise}\end{cases}[/tex]

so that

[tex]P(X>3)=\displaystyle\int_3^\infty f_X(x)\,\mathrm dx=\frac1{14}\int_3^9\mathrm dx=\frac37[/tex]