Answer:
10.94 g.
Explanation:
kt = ln [Aā]/[A]
k is the rate constant = 0.02665 minā»Ā¹.
t is the time = 104.0 min.
[Aā] is the initial percentage of radioisotope = 175.0 g.
[A] is the remaining percentage of radioisotope = ??? g.
āµ kt = ln [Ao]/[A]
ā“ (0.02665 minā»Ā¹)(104.0 min) = ln (175.0 g)/[A]
2.772 = ln (175.0 g)/[A]
15.99 = (175.0 g)/[A]
ā“ [A] = (175.0 g)/(15.99) = 10.94 g.