Answer:
264.6kJ
Explanation:
Assuming the water is pure, then it has a density of 1000kg/m³= 1g/cm³
1 liter will be equivalent to 1000cm³.
Mass will be: density×volume
1g/cm³×1000cm³=1000g
in kg it will be 1kg
The specific heat capacity of pure water is 4.2kJ/kgK
We use the formula MC∅ where ∅ is the temperature change.
Therefore the heat absorbed will be:
1kg×4.2kJ/kgK× (82-19)K= 264.6kJ
