moni134
moni134
08-03-2019
Mathematics
contestada
How do you do #1 & #2 ?
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Kamikazeminem
Kamikazeminem
08-03-2019
[tex]Answer: \\ 1. \: x = \frac{ {32}^{2} }{24} = \frac{128}{3} \\y = \sqrt{ {24}^{2} + {32}^{2} } = 40\\ z = \frac{32 \times 40}{24} = \frac{160}{3} \\ \\ 2. \: x = \sqrt{( {4 \sqrt{5} )}^{2} - {8}^{2} } = 4[/tex]
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