Respuesta :

Answer:

[tex]x=2-\sqrt{3}[/tex]

Step-by-step explanation:

we are given one of root as

[tex]x=2+\sqrt{3}[/tex]

since, this is a root of polynomial

and this sqrt roots

we know that

sqrt roots and complex roots of any polynomial always exists in conjugate form

For example:

if we have root as

[tex]x=a+\sqrt{b}[/tex]

then other root must be conjugate of it

[tex]x=a-\sqrt{b}[/tex]

because both roots makes polynomial of real coefficient

so, other root must be

[tex]x=2-\sqrt{3}[/tex]


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