Which shows the pre-image od quadrilateral w'x'y'z' before the figure was rotated according to the rule (x,y) -> (-x,-y)?

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JannetPalos JannetPalos · Answer 1 · 2019-01-06T10:58:40+01:00

Answer:

The pre-image of the quadrilateral is attached.

Step-by-step explanation:

Each point (x, y) is rotated with the rule (x, y) -> (-x, -y).

So, point W'(2, 3) was W(-2, -3) before rotation.

X'(6, 3) was X(-6, -3)

Y'(6, 4) was Y(-6, -4).

Z'(3, 5) was Z(-3, -5).

The pre-image of the quadrilateral is attached.

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MrRoyal MrRoyal · Answer 2 · 2021-09-18T00:30:37+02:00

When a shape is rotated, it must be rotated through a center of rotation.

See attachment for the pre-image of W'X'Y'Z

From the attached graph, we have:

[tex]W' = (2, 3)[/tex]

[tex]X' = (6, 3)[/tex]

[tex]Y' = (6, 4)[/tex]

[tex]Z' = (3, 5)[/tex]

The rotation rule is given as:

[tex](x,y) \to (-x,-y)[/tex]

When the rotation is reversed, the coordinates of the pre-image WXYZ are as follows:

[tex]W = (-2,-3)[/tex]

[tex]X = (-6,-3)[/tex]

[tex]Y = (-6,-4)[/tex]

[tex]Z =(-3,-5)[/tex]

The options are not given. So, I've added an attachment that illustrates the pre-image WXYZ