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An evil supervillian has launched a drone from his/her submarine. The drone's height, in meters above sea level, as a function of time, t , in seconds, is given by h ( t ) = − 4.9t^2 + 133t + 152

What is the maximum height? Round your answer to three decimal places.

Respuesta :

Answer:

the maximum height is 1054.500 meters

Step-by-step explanation:

h ( t ) = − 4.9t^2 + 133t + 152

a= -4.9 , b= 133  and c= 152

To find maximum height , we find vertex

[tex]x= \frac{-b}{2a}=\frac{-133}{2(-4.9)}= 13.5714 [/tex]

Now plug in 13.5714 for 't' in h(t)

[tex]h(t) =-4.9t^2 + 133t + 152[/tex]

[tex]h(t)=-4.9( 13.5714)^2 + 133( 13.5714)+ 152=1054.500[/tex]

the maximum height = 1054.500 meters

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