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1. 2(H-8)-h=h-16

A. H=8
B. H=-8
C. H= infinitely many solution
D. H= no solution

2. 3+6Z=13+6z

A. Z= -5/6
B. Z= 2 2/3
C. Z=infinitely many solutions
D. Z=no solution

Respuesta :

(1) C and (2) D

(1)

distribute the left side of the equation

2h - 16 - h = h - 16 ( simplify left side )

h - 16 = h - 16

Since both sides are equal, any value of h will make the equation true.

Hence there are infinitely many solutions to the equation → C

(2)

3 + 6z = 13 + 6z ( subtract 6z from both sides )

3 = 13 ← not possible

Hence there are no solutions to the equation → D



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