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What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x/3−1 ?

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Answer:

y= -3x+14

Step-by-step explanation:

To get the slope of the perpendicular line, get the negative reciprocal of the slope

if m=1/3, the slope of the perpendicular line is -3

Substitute the coordinates into the equation of the perpendicular line with the new slope and solve for b

2=4(-3) +b

2=-12+b

Add 12 to both sides

b=14

So, if m=-3 and b= 14 the line's equation is y= -3x+14